# Extract the disk space percentage capacity -- df dumps things out, sed strips the first line,
# awk grabs the fifth column, and cut removes the trailing percentage.
DISKSPACE=`df -H /dev/sda1 | sed '1d' | awk '{print $5}' | cut -d'%' -f1`
# Disk capacity threshold
ALERT=70
if [ ${DISKSPACE} -ge ${ALERT} ]; then
echo "Still enough disk space....${DISKSPACE}% capacity."
exit
fi
Thursday, January 20, 2011
bash script to check disk space
Need a script to check whether a certain drive is out of space or hits a certain threshold?
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here is a more efficient script I wrote.
ReplyDelete#!/bin/bash
> alert.txt
HOST=$(hostname)
THRES=20
COUNT=1
df -HP | grep -vE 'Filesystem|tmpfs' | awk '{ print $5 " " $6 }' |
while read space;
do
DISK=$(echo $space | cut -d "%" -f1)
DRIVENAME=$(echo $space | cut -d " " -f2)
if [ "$DISK" -ge "$THRES" ]
then
echo You have used "$DISK"% on drive "$DRIVENAME" on server "$HOST" >>alert.txt
fi
done
echo alert.txt | mail -s "Disk space Alert on server $HOST" root
Not sure why you consider this approach more efficient. But yes this would probably work too.
ReplyDeleteThanks for posting this. Helped me a lot.
ReplyDeletelinux check disk drive for errors
Of course the Roger's script is more efficient, clear, legible and a good seed for various tools you need to craft.
ReplyDeleteThanks
I was looking for something more efficient than my solution. But alas. Ok, so here's my $0.02
ReplyDeleteIn my case, I need to guarantee a certain amount of K are available. The output columns of "df" are not very standardized and in all situations. So be sure to check if yours is the one you want with "df -k | awk '{print $4}' ". The benefits from my approach:
* 1-liner.
* Only two process calls (useful in many instances)
* can be used as part of a shell-boolean expression (ie, if -then construct, boolean shortcut, etc)
* if mountpoint does not exist, exit code is 1 (false)
df -k | awk -v mountpt=/WHATEVER -v minreq=MIN-SPACE-IN-KB \
'$NF == mountpt { found=1; satisfy=($4 >= minreq) ? 1 : 0; } END { exit(!(found && satisfy)); }';
Here is a more compact, but functionally equivalent version:
df -k | awk -v t=/WHATEVER -v r=MIN-SPACE-IN-KB \
'$NF == t { s=($4 >= r) } END { exit(!s); }';